Recent Questions
Q: I want to be able to pull information into dynamic drop down menu from the mysql database.
A: You may generate a menu from a database or XML using any server-side script, e.g., PHP, ASP, VB, etc.
However, these scripts don't work inside of Javascript .js files, so,
you should move parameters of a menu from a .js file into an html-page, e.g.:
<!-- Deluxe Menu -->
<noscript><a href="http://deluxe-menu.com">Javascript Menu by Deluxe-Menu.com</a></noscript>
<script type="text/javascript"> var dmWorkPath = "menudir/";</script>
<script type="text/javascript" src="menudir/dmenu.js"></script>
<!-- (c) 2008, http://deluxe-menu.com -->
<script type="text/javascript" language="JavaScript1.2">
// and describe parameters of a menu
var parameter1=value1;
var parameter2=value2;
etc.
var menuItems = [
// here you generate items using server-side scripts (php, asp, vb, etc.)
];
</script>
The example of the menu working with PHP/MYSQL you can find here:
http://deluxe-menu.com/rq-loading-bar-MySQL-support.html
Q: I'm struggling with one last issue on my navigation. When you have a screen resolution about the same size as the site width, when a sub menu pops up, It displays sometimes to the left of the first drop down menu list rather than the left. Is there a way of changing the way this displays if the screen size is smaller than 800px wide or so.
A: If there is no enough room on the right side of your browser windowdrop down menu list submenus will be shown on the left side.
Q: How to set close javascript pop up menu effect in version 3.2?
A: You can use the following code to hide your javascript pop up menu
<script type="text/javascript">
javascript:document.getElementById('dm0m0').style.visibility='hidden';
</script>
Q: I am still struggling with multiple menus on one page.
It is probably something I am doing wrong, but I cannot see it.
A: Now you have:
var absolutePos=1;
var posX="10";
var posY="10";
So, both of your menus have the same absolute position.
You can use relative position and place your menu inside <table>. In this case you should write so:
var absolutePos=0;