Recent Questions
Q: I'm having trouble getting rid of a shadow the the right and bottom of a list menu java script, I don't see a parameter for it:
A: In your data .js file find the shadow section
var shadowLen=3;
var shadowColor="#777777";
var shadowTop=1;
and set
var shadowLen=0;
Q: Can I add the value of the parameter to the link where I want my application to go when I active a submenu in the menu script?
A: Actually you can add php code inside menu links.
If you define your parameter in .js file you should write yourlinks in the following way, for example:
<?
....
$key = 123456;
....
?>
["Home","www.domain.com/home.php?key=<? echo $key ?>", "", "", "", "", "", "", "", ],
If you define your key parameter in the php file you should move your
menuItems into your php page directly:
<?
....
$key = 123456;
....
?>
<script type="text/javascript">
var tmenuItems = [
['Deluxe Menu','http://deluxe-menu.com','icon.gif',,,,,],
['Deluxe Tree','http://deluxe-tree.com','icon.gif',,'New!',,,],
['Deluxe Tabs','http://deluxe-tabs.com','icon.gif',,'New!',,,],
["Home","www.domain.com/home.php?key=<? echo $key ?>", "", "", "", "", "", "", "", ],
];
dm_init();
</script>
Q: I am interested in purchasing your product for use in my company's website code. My clients are not tech-savy, and I do not want to include any code that will generate concern or problems on the user end.
Is there a way to use the JavaScript menus without generating the warning as mentioned in the subject? I know how to allow the active content on my web browser, but I want code that will not require such actions on their browsers.
A: Thanks for your interest in our products.
Your clients should check browser settings.
Unfortunately, we can't affect on the browser behavior in this case.
Q: I am still struggling with multiple menus on one page.
It is probably something I am doing wrong, but I cannot see it.
A: Now you have:
var absolutePos=1;
var posX="10";
var posY="10";
So, both of your menus have the same absolute position.
You can use relative position and place your menu inside <table>. In this case you should write so:
var absolutePos=0;