Recent Questions
Q: I try to use the javascript menu popups to show an image; then when the mouse is over the image I dynamically generate a panel of http links. It works perfectly, but the problem is that I would like to do the same with several images (for instance 2) and different links : I'm not able to do that, whether I change the value of menuItems var or not, I display the same link values on both images (it seems menuItems is a global var and can be set only once).
Have you heard about this problem and could you give me a solution (this is a bit urgent, I have sold this solution to my customers) ?
A: See how you should call dm_popup() functions:
<img src="../../../../fileadmin/img/flag_de.gif" width="50" onMouseOver="return dm_popup(0, 2000, event);" style="cursor: pointer;">
// 0 - is ID of the first menu
....
<img src="../../../../fileadmin/img/flag_fr.gif" width="50" onMouseOver="return dm_popup(1, 2000, event);" style="cursor: pointer;">
// 1 - is ID of the second menu
// 2 - is ID of the third menu
... and so on.Q: Hi there ... a while ago I had asked you what I need to change to prevent exit pops from being activated, but I don't think it's working.
For example, a regular link that I want:
onClick="exit=false"
How do I do it with dhtml vertical menu?
Before, in the "text" box in the "Item Parameters" window, you had me do the following:
<span onClick='exit=false;'>click here</span>
But that doesn't seem to work. Any other suggestions? Thanks very much.
A: I suppose that you should move menuItems from the data file to yourhtml page directly (where you define exit variable).
<script>
menuItenms = [
...
],
</script>
Q: I want to use single css drop down menu bar for each page without applying HTML Code for each page separatly.I mean to use CSS Menu as per our .JS Menu.
A: Unfortunately it is not possible with css menu.
On each page you should call css file with styles:
<link href="menu.css" rel="stylesheet" type="text/css" />
and add code for the menu on each page in the place where you want to have a menu, forexample:
<ul class="cssMenu cssMenum">
<li class=" cssMenui"><a class=" cssMenui" href="testlink.html">Home</a></li>
<li class=" cssMenui"><a class=" cssMenui" href="#"><span><img class="def" src="default.files/icon1.gif"/>
<img class="over" src="default.files/icon1o.gif">Product Info</span>
<![if gt IE 6]></a><![endif]><!--[if lte IE 6]><table><tr><td><![endif]-->
<ul class=" cssMenum">
<li class=" cssMenui"><a class=" cssMenui" href="testlink.html"><img class="def" src="default.files/icon2.gif"/>
<img class="over" src="default.files/icon2o.gif">Features</a></li>
</ul>
<!--[if lte IE 6]></td></tr></table></a><![endif]-->lt;/li>
<li class=" cssMenui"><a class=" cssMenui" href="testlink.htm">
<img class="def" src="default.files/icon1.gif"/>
<img class="over" src="default.files/icon1o.gif">Contact Us</a></li>
</ul>
You can also try to use frames.
Also you can use aserver-side script (php, asp, vb, etc.) to generate html pages fromtemplates on your server.
Q: I have just purchased your menus and no matter where I place the code, the pull down menu in javascript always appears in the top left of the page, I need it elsewhere obviously but it simply won't move.. How do I do this?
A: You're using absolute position for the menu now. You should userelative position in that case. Change the following parameters:
var absolutePos=0;
var posX="0px";
var posY="0px"; >Kehren Sie zu Neuen Fragen zurück
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