Recent Questions
Q: I would like to add a javascript link but cannot seem to get it handle the event as a tag or onclick event. I just want to grab the current page, insert it into a string, and go off to the page it specifies. Can this be done?
A: You're able to use Javascript for each item, for example:
var menuitems = [
["item text", "javascript:your_code_here"]
];
Unfortunately, you can't assign onmouseover/onClick event to each item.
However, you can achieve this by using standard html objects within items, for example:
var menuitems = [
["<div onClick='your_code_here'>item text</div>", "index.html"]
];
Q: I have been working with on a site and I am kind stack using the program. I want to use the tree option but not all “buttons” need to have subcategories. For example:
Category 1
Sub-menu 1-1
Sub-menu 1-2
Sub-menu 1-3
Category 2
Sub-menu 2-1
Sub-menu 2-2
Sub-menu 2-3
Category 3
Category 4
When someone click on the “Category 1” or “Category 2”, I want them to see the sub-menus. However, when some click on “Category 3” or “Category 4”, I would like to have it open the appropriate page. How do I do this? This will make a lot easier because not all buttons need to have sub-menus… I hope that makes sense and you can help me on getting this done.
A: You cannot use links for the top items in XP Style only.
var tXPStyle=1;
but you can write:
["<a href='http://deluxe-menu.com'>Item 45</a>","", "", "", "", "", "", "", "", ],
Q: I am trying to change the Width for only one javascript popup menu item and going to the below menu individual style and changing the smwidth .
But this is not changing.
A: You should assign Individual Submenu Style for the items.
You can assign it in the "Item Parameters" window.
Select for example the first item in submenu and assign IndividualSubmenu Style.
Q: I notice in your examples that your menus are horizontal and then drop down.
Is it possible to configure your javascript menu generator for vertical menus?
A: Yes, it is possible.
You should set the following parameter:
var isHorizontal=0;