Recent Questions
Q: I downloaded the new version of dhtml menu source code copied the files over to my folder this menu was made with3.0 the files I copied over is 3.2 and now I get an error.
A: Now you have:
var fontStyle=["nirmal 12px Trebuchet MS, Tahoma","nirmal 12px Trebuchet MS, Tahoma"];
It is not correct. You should write:
var fontStyle=["normal 12px Trebuchet MS, Tahoma","normal 12px Trebuchet MS, Tahoma"];
Q: Is it possible to centere mouse over drop down menu?
A: Check that you set relative position for the menu:
var absolutePos=0;
var posX="0px";
var posY="0px";
Place your menu in DIV or TABLE with center alignment.
Q: Can I use data from a SQL server using ASP for the dhtml xml menu?
A: You may generate a menu from a database or XML using any server-side script, e.g., PHP, ASP, VB, etc.However, these scripts don't work inside of Javascript .js files, so, you should move parameters of a menu from a .js file into an html-page, e.g.:
<!-- Deluxe Menu -->
<noscript><a href="http://deluxe-menu.com">Javascript Menu by Deluxe-Menu.com</a></noscript>
<script type="text/javascript"> var dmWorkPath = "menudir/";</script>
<script type="text/javascript" src="menudir/dmenu.js"></script>
<!-- (c) 2006, http://deluxe-menu.com -->
<script type="text/javascript" language="JavaScript1.2">
// and describe parameters of a menu
var parameter1=value1;
var parameter2=value2;
etc.
var menuItems = [
// here you generate items using server-side scripts (php, asp, vb, etc.)
];
</script>
Unfortunately we don't have examples with ASP and SQL.
The example of the menu working with PHP/MYSQL you can find here:
http://deluxe-menu.com/rq-loading-bar-MySQL-support.html
Q: I have just purchased your menus and no matter where I place the code, the pull down menu in javascript always appears in the top left of the page, I need it elsewhere obviously but it simply won't move.. How do I do this?
A: You're using absolute position for the menu now. You should userelative position in that case. Change the following parameters:
var absolutePos=0;
var posX="0px";
var posY="0px"; >Kehren Sie zu Neuen Fragen zurück