Recent Questions
Q: There seems to be a "glitch" when I use Firefox.
I have rebuilt the page twice but I always end up with themenu floating to the left, instead of under the main menu (the second or third mouseover will correct the issue). Also, sometimes I have to mouseover twice before the submenu comes up (in I.E.).
I have validated...however I wondered if there could be a conflict in the javascripting (yours and mine). Any suggestions?
A: The reason is in your <!DOCTYPE>.
Try to specify units in "px".
var menuWidth="780px";
var menuHeight="27px";
var smWidth="200px";
var smHeight="200px";
It's necessary to specify exact value for Mozilla browsers. It helpsto position menus correctly.
You can also try to set the following parameter:
var dm_writeAll=1;
Q: Do you by chance have an example of the java popup menu working with XML?
A: You may generate a menu from a database or XML using any server-side script, e.g., PHP, ASP, VB, etc.
However, these scripts don't work inside of Javascript .js files, so,you should move parameters of a menu from a .js file into an html-page, e.g.:
<!-- Deluxe Menu -->
<noscript><a href="http://deluxe-menu.com">Javascript Menu by Deluxe-Menu.com</a></noscript>
<script type="text/javascript"> var dmWorkPath = "menudir/";</script>
<script type="text/javascript" src="menudir/dmenu.js"></script>
<!-- (c) 2008, http://deluxe-menu.com -->
<script type="text/javascript" language="JavaScript1.2">
// and describe parameters of a menu
var parameter1=value1;
var parameter2=value2;
etc.
var menuItems = [
// here you generate items using server-side scripts (php, asp, vb, etc.)
];
</script>
The example of the menu working with PHP/MYSQL you can find here:http://deluxe-menu.com/rq-loading-bar-MySQL-support.htmlQ: Whenver I choose the enable Ajax feature and set the AjaxCount to 0, my menus don't pop out anymore. How do I get it to pop out?
A: That variable set the maximal number of submenus that will be loadedfrom server on your page.
If you don't know exact number of submenus you can set a big value forthis parameter.
If you set var dmAJAXCount=0; you cannot see you submenus.
To enable Ajax feature you should set, for example:
var dmAJAX=1;
var dmAJAXCount=100;
Q: We purchased the Deluxe Menu a few months ago and are extremely happy with the product. We have been getting great compliments about our new navigation system.
The menu has over 500 links and functions like a dream! One issue I am having, that I just cannot seem to figure out how to fix, is the following:
Our nav menu is displayed approx. 70 pixels from the top of the browser window. On the drop down links that have a number of items (example 1 in the image below), they display underneath the menu, however on the links that have only a few items, they display above the menu bar in java script as in example 2 in the image below.
How can I set it so that no matter how many drop-down items there are, they always display under the menu bar in java script, not on top?
A: Try to set the following parameter:
var subMenuVAlign="top";