Recent Questions
Q: Is there a way I can do an include of a separate file that would contain the
var menuItems = [];
A: You can delete var menuItems = []; and dm_init(); from your data.jsfile and paste it into your html page or in the other file.
You should call at first data.js file with the parameters and thanmenuItems = []; and dm_init();.
Q: Can I make dhtml menu sample so a user can open a link on a Deluxe-Menu in a new browser tab instead of a new window using IE?
I really like your menu system.
A: You can try to write the following code for your items:
["<a href='index.html' target='_blank' class='home'>Home</a>","", "", "", "", "", "", "", "", ],
And create styles
.home{
color: #FFFFFF;}
.home:hover{
color: #FFBEBE;}
Q: I will probably purchase your developer version mostly because I want access to the 600 icons....
1) Do you offer access to these icons with any other license for css drop down menu?
2) I develop sites for several clients, what is involved for them to make small changes to their menus... i.e. add or delete a menu item or sub-item... Will they need to purchase a license to make changes?
3) Does the developer version access your site at runtime? I do not have a problem registering my client sites and getting a key... I just want to make sure at runtime their site does not contact yours.
A: 1) Icon collection is available in Developer licenses only.
2) No, there is no need to purchase the license in that case.
3) No, script doesn't access our site at runtime.
Developer version of the script doesn't check reg. keys at all.
With the Developer license you can use the menu on an unlimited number of Internet or Intranet sites and on the local machines.
This version of the css drop down menu doesn't check keys and it isn't bound to a domain name,so it can be used with an application that doesn't have a fixed domain name.
Q: I'm trying to display the submenus to the left of the menu. I searched your questions and found one that said to use the following:
var smViewType=2;
I added this but it didn't do anything.
A: Try to use this parameter:
var subMenuAlign = "left";