Recent Questions
Q: How I make sure, that long menu items in dhtml menu sample can wrap into two lines?
A: You should set the following parameter:
var noWrap=0;
Or use standard <br> tags inside item's text:
["International Music X Home<br>Decoration X Books","", "", "", "", "", "0", "0", "", "", "", ],Q: I am rewriting my homepage in CSS but now I have another problem with the DeLuxe menu.
The javascript top menu is well positioned on the page but the submenus are not.
The submenus are not positioned aside the javascript top menu but lower and far to much to the right.
I changed the variables
var posX = 100;
var posY = 100;
var absolutePos = 1;
var topDX = 0;
var topDY = 0;
var DX = -3;
var DY = 0;
var subMenuAlign = "left";
var subMenuVAlign = "top";
Sometimes when I change the variables the submenus are well positioned and then, after enlarging the IE-window, they are not.
What can I do?
A: It is possible that you have some problems with your css styles.
See, the problem is that the javascript top menu can't get css properties of the object if they are described in separate .css block (or file).
In other words, you can't get the value of "POSITION: absolute" attribute of the object if the object doesn't have this property within inline style (style="POSITION:absolute;"). To get the value you should move .css style into style="" attribute.
Please, try to add your
css file -> inline css, for example:
You should add style="POSITION: absolute;"
to the
<div id="block">
Q: I'm trying to display the submenus to the left of the vertical navigation bar.
A: Try to use the following parameter:
var subMenuAlign = "left";
Q: I have used your Deluxe-menu on my websit. With the browser Opera I have problems with the dhtml scrolling menu item-color. If I select the menu at the first time, the item color is black. After select a menu item the menu item color is #f0e4cc, this is correct. After re-select the menu the item color is #f0e4cc also. After browser re-start the menu item color is black :-(
A: See it is not correctly to write colors in the following way (without # symbol):
var fontColor=["f0e4cc","f0e4cc"];
You should write:
var fontColor=["#f0e4cc","#f0e4cc"];
Your menu will work correctly in all browsers in that case.