Recent Questions
Q: Hi there, hope someone could help me out.
We have recently purchased your menu product, and I would like to know how I indicate on a javascript slide menu, the root node that was selected. So in other words, if I have a horizontal navigation and I select the 3rd index along the menu and select something from this, how can I make the 3rd index highlighted?
I am not sure how else to phrase this question and hope this makes sense. You help will be appreciated.
A: You can find more info here:
http://www.deluxe-menu.com/highlighted-items-sample.html
Deluxe Menu has only two states normal and mouseover.
Try to do the following things:
- delete var pressedItem=1; parameter from your data file
- set correct parameter on each page before you call data file, forexample:
<noscript><a href="http://deluxe-menu.com">Javascript Slide Menu by Deluxe-Menu.com</a></noscript>
<script type="text/javascript"> var dmWorkPath = "menudir/";</script>
<script type="text/javascript" src="menudir/dmenu.js"></script>
<script type="text/javascript"> var pressedItem=3;</script>
...
<script type="text/javascript" src="menudir/data.js"></script>
You can also set a pressed item using Javascript API:
function dm_ext_setPressedItem (menuInd, submenuInd, itemInd, recursion)
Sets a current pressed item.
menuInd - index of a menu on a page, >= 0.
submenuInd - index of a submenu, >= 0.
itemInd - index of an item, >=0.
recursion = true/false - highlight parent items.
But notice, to use dm_ext_setPressedItem() you should know ID of selected item and subitem. You can't get this ID after you reload your page. That is why you should write your own code on PHP.
Q: I want to use single css drop down menu bar for each page without applying HTML Code for each page separatly.I mean to use CSS Menu as per our .JS Menu.
A: Unfortunately it is not possible with css menu.
On each page you should call css file with styles:
<link href="menu.css" rel="stylesheet" type="text/css" />
and add code for the menu on each page in the place where you want to have a menu, forexample:
<ul class="cssMenu cssMenum">
<li class=" cssMenui"><a class=" cssMenui" href="testlink.html">Home</a></li>
<li class=" cssMenui"><a class=" cssMenui" href="#"><span><img class="def" src="default.files/icon1.gif"/>
<img class="over" src="default.files/icon1o.gif">Product Info</span>
<![if gt IE 6]></a><![endif]><!--[if lte IE 6]><table><tr><td><![endif]-->
<ul class=" cssMenum">
<li class=" cssMenui"><a class=" cssMenui" href="testlink.html"><img class="def" src="default.files/icon2.gif"/>
<img class="over" src="default.files/icon2o.gif">Features</a></li>
</ul>
<!--[if lte IE 6]></td></tr></table></a><![endif]-->lt;/li>
<li class=" cssMenui"><a class=" cssMenui" href="testlink.htm">
<img class="def" src="default.files/icon1.gif"/>
<img class="over" src="default.files/icon1o.gif">Contact Us</a></li>
</ul>
You can also try to use frames.
Also you can use aserver-side script (php, asp, vb, etc.) to generate html pages fromtemplates on your server.
Q: The AJAX sample for tree menu script on website does not have any styling applied at the moment.
I am assuming that it would support full styling with AJAX as well.
Is this correct?
A: You can use any style and templates for the AJAX sample.
Create a menu and set style you need using Individual Item Styles.
To enable AJAX Tree Menu use the following menu parameters:
var tajax=1;
Then set your menu in such way:
var tmenuItems = [
["Deluxe Tree: XP Style","", "", "", "", "XP Title Tip", "", "0", "", "data-samples/data-ajax5.js", ],
["+Samples Gallery","", "", "", "", "XP Title Tip", "", "0", "0", "", ],
["|Samples Block 1","", "", "", "", "", "", "", "", "data-samples/data-ajax.js", ],
["|Samples Block 2","", "", "", "", "", "", "", "", "data-samples/data-ajax.js", ],
["|Samples Block 3","", "", "", "", "", "", "", "", "data-samples/data-ajax.js", ],
];
Each .js file must contain menuItems variable for the submenu in the following format:
var tmenuItems = [
[text, link, icon1, icon2, icon2, tip, target, itemStyle, submenuStyle, jsFileName],
];
Where jsFileName - .js filename on the server that contains tmenuItems variable for the submenu.
For example:
var tmenuItems = [
["Home","testlink.htm", "", "", "", "Home Page Tip", "", "", "", "", ],
["Product Info","", "", "", "", "Product Info Tip", "", "", "", "data-samples/data-ajax2.js", ],
["Samples","", "", "", "", "Samples Tip", "", "", "", "data-samples/data-ajax4.js", ],
["Purchase","testlink.htm", "", "", "", "Purchase Tip", "", "", "", "", ],
["Support","", "", "", "", "Support Tip", "", "", "", "", ],
["|Write Us","mailto:[email protected]", "", "", "", "", "", "", "", "", ],
];
Q: Using the example menu you have, how do i make the sub-menu for the 'Sample' menu item a multi-column and leave the 'Product Info' menu item as is.
I only want certain sub-menus to have multi-columns. I don't want all menu items to have a multi-column sub.
A: Please, see the attached example.
You should use individual styles.
var menuStyles = [
["smColumns=2"],
["smColumns=1"], //style 1
];
...
["More Samples","testlink.htm"],
["|Group 1","", , , , , "3", "1", , ], //assign style 1
Try that.