Recent Questions
Q: I have been using the DHTML Menu program for years and they are working good.
But I found an office where the javascript tree menu example just simply does'nt appear.
I am curious about it, why just in that office the Menu is not working.
I can note than other javascript routines I put on my page are not working neither.
Can you give me some idea of what can I check on the computers?
Something on the explorer? (IE6) , or a kind of program?
A: Your browser has JavaScript option disabled.
It means that no one JavaScript element can be run.
You should to enable JavaScript in IE:
Tools -> Internet Options -> Security -> Custom level... -> Scripting -> Active Scripting = Enable
There is no way to enable these preferences automatically, in othercase there are no reasons to create security preferences.
You can use search engine friendly code, so you'll see all yourlinks (for the main items and submenus) when your security settings in IE doesn't allow Javascript.
You can generate search engine friendly code.
Deluxe Menu is a search engine friendly menu since v1.12.
To create a search engine friendly menu you should add additional html code within your html page:
<div id="dmlinks">
<a href="http://deluxe-menu.com">menu_item_text1</a>
<a href="http://deluxe-tree.com">menu_item_text2</a>
...etc.
</div>
To generate such a code use Deluxe Tuner application.
You can find this GUI in the trial package.
Run Tuner, load your menu and click Tools/Generate SE-friendly Code (F3).
Q: Is it possible to have your menu mouseover call one of my functions?
I need to change some text on the screen based on which menu itemis highlighted.
A: Each menu items can include any html code.
So, you can include your own objects with onmouseover event, forexample:
var menuItems = [
["<div onmouseover='yourFunc()'>item text</div>"]
];
Where yourFunc() is Javascript function.
Q: I have been working with the trial package for the last couple of days, of which I have been really impressed with. However there have been a couple of things that have frustrated me greatly...
The natural place that I first tried was replacing the "content1" line with a direct URL in the var bmenuItems section but this made no difference at all. I am also trying to work out what each set of "" equate to as I have found a couple of pages on the Internet very similar to this but none of them have nine different sections.
["Home","content1", "", "", "", "", "1", "", "", ],
Is it possible to allow one of the tabs on this template to just open another page? I look forward to your response in regards to these questions and hope to hear from you again soon so that I can crack on with this project.
A: You can't assign links in Dhtml Tabs when you're using var tabMode = 0;.
You can assign only the object's ID of <div> on your page.
Try to set var tabMode = 1;
and use links for your items.
Q: I need to work it with PHP/MySQL. I have found some information on it in your Support section, but have problems to understand and wonder if you have more information or a working sample of the loading bar with PHP/ MySQL.
A: Info about generating menu (menu items )from a database, please, see:
http://deluxe-menu.com/generate-menu-from-database-xml-php-asp-vb-support.html
Please, see the example of .php file.
The content of .php file depends on your database structure.
<?php
// The example for PHP/MySQL.
// MySQL database has the table "menuTable" that contains data for menu items.
// The table has the following fields:
// 1. "text" - item text
// 2. "link" - item link
// 3. "icon1" - item icon (normal state)
// 4. "icon2" - item icon (mouseover state)
function getMenuItems()
{
$jsItems = '';
// Select all records from table "menuTable"
$allItems = mysql_query('SELECT * FROM menuTable;');
// Extract items data from database and build Javascript code for menuItems
while ($itemData=mysql_fetch_array($allItems))
{
$jsItems .= '["'.$itemData['text'].'", "'.$itemData['link'].'", "'.$itemData['icon1'].'", "'.$itemData['icon2'].'"],';
}
// Return Javascript code
return $jsItems;
}
?>
<script>
var menuParam1 = value1;
var menuParam2 = value2;
var menuParam2 = value2;
...
var menuItems = [
<?php
// Write Javascript code for menu items
echo getMenuItems();
?>
];
</script>