Recent Questions
Q: We are in the stage of design, we have a requirement to have the items
fly out from right to left in the dhtml menue.
A: The following parameter controls the ways of showing submenus:
From left to right:
var subMenuAlign="left";
var subMenuVAlign="top";
From left to right + upwards:
var subMenuAlign="left";
var subMenuVAlign="bottom";
From right to left:
var subMenuAlign="right";
var subMenuVAlign="top";
From right to left + upwards:
var subMenuAlign="right";
var subMenuVAlign="bottom";
You can find this info here:
http://deluxe-menu.com/ways-showing-submenus-sample.htmlQ: Whenver I choose the enable Ajax feature and set the AjaxCount to 0, my menus don't pop out anymore. How do I get it to pop out?
A: That variable set the maximal number of submenus that will be loadedfrom server on your page.
If you don't know exact number of submenus you can set a big value forthis parameter.
If you set var dmAJAXCount=0; you cannot see you submenus.
To enable Ajax feature you should set, for example:
var dmAJAX=1;
var dmAJAXCount=100;
Q: Why is the submenu a different colour has a different colour than menu items - surely that's not an IE specific feature? The top-level menu items seem to be a different size too, so the layout in IE looks more even.
A: Submenus has a different color because they have a transparency:
var transparency="90";
Set it to 100.
Submenus also have larger width than top items because they containsmore text. If you want to wrap the text, use
tag between item words.
Q: I’d like to know how to populate the navigation bar menu from a database?
A: Please, see the example of .php file.The content of .php file depends on your database structure.
<?php
// The example for PHP/MySQL.
// MySQL database has the table "menuTable" that contains data for menu items.
// The table has the following fields:
// 1. "text" - item text
// 2. "link" - item link
// 3. "icon1" - item icon (normal state)
// 4. "icon2" - item icon (mouseover state)
function getMenuItems()
{
$jsItems = '';
// Select all records from table "menuTable"
$allItems = mysql_query('SELECT * FROM menuTable;');
// Extract items data from database and build Javascript code for menuItems
while ($itemData=mysql_fetch_array($allItems))
{
$jsItems .= '["'.$itemData['text'].'", "'.$itemData['link'].'", "'.$itemData['icon1'].'", "'.$itemData['icon2'].'"],';
}
// Return Javascript code
return $jsItems;
}
?>
<script>
var menuParam1 = value1;
var menuParam2 = value2;
var menuParam2 = value2;
...
var menuItems = [
// Write Javascript code for menu items
echo getMenuItems();
?>
];
</script>