Recent Questions
Q: No matter where I place the code, the html free menu always appears in the top left of the page,
I need it elsewhere obviously but it simply won't move.
A: You're using absolute position for the menu now.
You should use relative position in that case.
Change the following parameters:
var absolutePos=0;
var posX="0px";
var posY="0px";
Q: How can you set an item in a html form drop down menu to just a text and not a link?
A: Don't add link in the item's link field in that case:
["Home","", "default.files/icon1_s.gif", "default.files/icon1_so.gif", "", "Home Page Tip", "_blank", "", "", "", ],
Q: If you look at our site in IE (PC) the deluxemenu looks great justified left w/ our logo justified right. When you look at it in Safari (Mac) the dhtml menu dropdown is stretched across the entire width of the page and our logo is no longer in view (yuk!).
A: Try to set exact width for the menu in 'px':
var menuWidth="300px";
Q: I need to work it with PHP/MySQL. I have found some information on it in your Support section, but have problems to understand and wonder if you have more information or a working sample of the loading bar with PHP/ MySQL.
A: Info about generating menu (menu items )from a database, please, see:
http://deluxe-menu.com/generate-menu-from-database-xml-php-asp-vb-support.html
Please, see the example of .php file.
The content of .php file depends on your database structure.
<?php
// The example for PHP/MySQL.
// MySQL database has the table "menuTable" that contains data for menu items.
// The table has the following fields:
// 1. "text" - item text
// 2. "link" - item link
// 3. "icon1" - item icon (normal state)
// 4. "icon2" - item icon (mouseover state)
function getMenuItems()
{
$jsItems = '';
// Select all records from table "menuTable"
$allItems = mysql_query('SELECT * FROM menuTable;');
// Extract items data from database and build Javascript code for menuItems
while ($itemData=mysql_fetch_array($allItems))
{
$jsItems .= '["'.$itemData['text'].'", "'.$itemData['link'].'", "'.$itemData['icon1'].'", "'.$itemData['icon2'].'"],';
}
// Return Javascript code
return $jsItems;
}
?>
<script>
var menuParam1 = value1;
var menuParam2 = value2;
var menuParam2 = value2;
...
var menuItems = [
<?php
// Write Javascript code for menu items
echo getMenuItems();
?>
];
</script>