Recent Questions
Q: Whenver I choose the enable Ajax feature and set the AjaxCount to 0, my menus don't pop out anymore. How do I get it to pop out?
A: That variable set the maximal number of submenus that will be loadedfrom server on your page.
If you don't know exact number of submenus you can set a big value forthis parameter.
If you set var dmAJAXCount=0; you cannot see you submenus.
To enable Ajax feature you should set, for example:
var dmAJAX=1;
var dmAJAXCount=100;
Q: There are two of your menus that we wish to incorporate into one. Our main left hand side vertical navigation menu would be an accordion menu. When you click on products in the accordion menu, it would drop down with an indented sub menu. When you hover over a link in the sub menu, your Javascript Scrolling Menu - Smart Scrollable Feature would allow us to have a scrolling sub menu.
I guess my question is can you have two javascript dhtml scroll menus working together in the same page?
A: I'm not sure I understand your question.
Why you should create two menus in that case?
You can create only one vertical menu (left menu) with all submenusand set smart scrollable feature:
var smSmartScroll=1;
That is all. Please try the trial version.
Q: I need to work it with PHP/MySQL. I have found some information on it in your Support section, but have problems to understand and wonder if you have more information or a working sample of the loading bar with PHP/ MySQL.
A: Info about generating menu (menu items )from a database, please, see:
http://deluxe-menu.com/generate-menu-from-database-xml-php-asp-vb-support.html
Please, see the example of .php file.
The content of .php file depends on your database structure.
<?php
// The example for PHP/MySQL.
// MySQL database has the table "menuTable" that contains data for menu items.
// The table has the following fields:
// 1. "text" - item text
// 2. "link" - item link
// 3. "icon1" - item icon (normal state)
// 4. "icon2" - item icon (mouseover state)
function getMenuItems()
{
$jsItems = '';
// Select all records from table "menuTable"
$allItems = mysql_query('SELECT * FROM menuTable;');
// Extract items data from database and build Javascript code for menuItems
while ($itemData=mysql_fetch_array($allItems))
{
$jsItems .= '["'.$itemData['text'].'", "'.$itemData['link'].'", "'.$itemData['icon1'].'", "'.$itemData['icon2'].'"],';
}
// Return Javascript code
return $jsItems;
}
?>
<script>
var menuParam1 = value1;
var menuParam2 = value2;
var menuParam2 = value2;
...
var menuItems = [
<?php
// Write Javascript code for menu items
echo getMenuItems();
?>
];
</script>
Q: I’m setting an after item image as follows (this code was generated by Deluxe Tuner, not by hand/text editor):
var afterItemImage=["designimgs/btn-ico.gif","designimgs/btn-ico-active.gif"];
var afterItemImageW=8;
var afterItemImageH=7;
As you can see, the after item image is not appearing in my access drop down menu – do you have any idea why that would be/how to fix?
A: You should create Individual style and assign it for the top access drop down menu items:
var itemStyles = [
["itemBackImage=designimgs/blank.gif,designimgs/blank.gif", "beforeItemImage=designimgs/blank.gif,designimgs/blank.gif", "afterItemImage=designimgs/btn-ico.gif,designimgs/btn-ico-active.gif", "beforeItemImageW=1","afterItemImageW=8", "beforeItemImageH=1","afterItemImageH=7","itemBorderWidth=0"],
];